当前位置: X-MOL 学术J. Fluorine Chem. › 论文详情
Our official English website, www.x-mol.net, welcomes your feedback! (Note: you will need to create a separate account there.)
Unsaturated nitrogen compounds containing fluorine. Part 16. The synthesis of 3,5-bis(trifluoromethyl)-1H-1,2,4-triazole and some 4-substituted derivatives from 2,5-dichloro-1,1,1,6,6,6-hexafluoro-3,4-diazahexa-2,4-diene
Journal of Fluorine Chemistry ( IF 1.7 ) Pub Date : 1995 , DOI: 10.1016/0022-1139(94)03199-a
Mohamad M. Abdul-Ghani , Anthony E. Tipping

The dichloroazine 5 has been converted into the monoaminoazines CF3C(NHR)=NN=CClCF3 (6) [a, R = Ph (89%); b, R = H (81%); c, R = Me (89%); d, R = CH2CO2Me (96%); e, R = CH2CO2Et (95%)] and the diaminoazines CF3C(NHR) = NN = C(NHR)CF3 (4) [c, R = H (96%); d, R = Me (94%); e, R = CH2CO2Me (50%); f, R = CH2CO2Et (77%)] by reaction with ammonia or the appropriate primary amino compound; with hydroxylamine the syn-oxime CF3CCl = NNHC(CF3) = NOH (8) (86%) was formed. The mixed diaminoazines CF3C(NHR) = NN = C(NHR′)CF3 (4) [g, R = H, R′ = Ph; h, R′ = Me, R′ = H; i, R = Me, R′ = CH2CO2Me; j, R = CH2CO2Me, R′ = Ph (92%–96%)] have been synthesised from the monoaminoazines 6a-d. A solution of the diaminoazine 4c, heated in ethanol under reflux, gave 3,5-bis(trifluoromethyl)-1H,2,4-triazole (1a) (28%) and its ammonium salt NH4+[C2N3(CF3)2] (7b) (54%), while the azines 4g and 4j under the same conditions each afforded 4-phenyl-3,5-bis(trifluoromethyl)-4H-1,2,4-triazole (2c) (ca. 85%). Thermolysis of the diaminoazines 4c-f and 4h in vacuo over the range 120–150 °C gave the following results: 4c → 7b (98%); 4d → MeNH3+ [C2N3(CF3)2] (7c) (ca. 26%)+Me4N+ [C2N3(CF3)2] (7d) (ca. 13%) + 4-methyl-3,5-bis(trifluoromethyl)-4H-1,2,4-triazole (2b) (54%) + 1-methyl-3,5-bis(trifluoromethyl)-1H-1,2,4-triazole (1b) (1.5%); 4e → the 4-carbomethoxymethyltriazole (2e) (93%); 4f → the 4-carboethoxymethyltriazole (2f) (82%); 4h → 1a (11%) + 2b (54%) + 7c (31%). Treatment of salt 7b with aqueous hydrochloric acid afforded the triazole 1a (75%).

中文翻译:

含氟的不饱和氮化合物。第16部分。由2,5-二氯-1,1,1,1,6,6,6-合成3,5-双(三氟甲基)-1 H -1,2,4-三唑和一些4-取代的衍生物六氟-3,4-二氮杂六-2,4-二烯

二氯嗪5已经转化为单氨基嗪CF 3 C(NHR)= NN = CClCF 3(6)[a,R = Ph(89%); n = 1。b,R = H(81%);c,R = Me(89%);d,R = CH 2 CO 2 Me(96%);e,R = CH 2 CO 2 Et(95%)]和二氨基嗪CF 3 C(NHR)= NN = C(NHR)CF 3(4)[c,R = H(96%);e,R =H(96%)。d,R = Me(94%);e,R = CH 2 CO 2 Me(50%);f,R = CH 2 CO 2 Et(77%)]与氨或适当的伯氨基化合物反应;与羟胺的合成-肟CF 3 CCl = NNHC(CF 3)=生成NOH(8)(86%)。混合的二氨基嗪CF 3 C(NHR)= NN = C(NHR')CF 3(4)[g,R = H,R'= Ph; h,R'= Me,R'= H;i,R = Me,R′= CH 2 CO 2 Me;j,R = CH 2 CO 2 Me,R'= Ph(92%–96%)]是由单氨基嗪6a-d合成的。将二氨基嗪4c的溶液在乙醇中加热回流,得到3,5-双(三氟甲基)-1 H,2,4-三唑(1a)(28%)及其铵盐NH 4 + [C 2 N 3(CF 32 ] -(7b)(54%),而在相同条件下的嗪4g和4j各自提供4-苯基-3,5-双(三氟甲基)-4 H -1,2,4-三唑(2c)(约85 %)。二氨基嗪4c-f和4h在真空中于120–150°C范围内的热解得到以下结果:4c→7b(98%);4d→MeNH 3 + [C 2 N 3(CF 32 ] -(7c)(约26%)+ Me 4 N + [C 2 N 3(CF 32 ] -(7d)(约13%) %)+ 4-甲基-3,5-双(三氟甲基)-4 H-1,2,4-三唑(2b)(54%)+ 1-甲基-3,5-双(三氟甲基)-1 H -1,2,4-三唑(1b)(1.5%); 4e→4-碳甲氧基甲基三唑(2e)(93%); 4f→4-羧乙氧基甲基三唑(2f)(82%); 4h→1a(11%)+ 2b(54%)+ 7c(31%)。用盐酸水溶液处理盐7b,得到三唑1a(75%)。
更新日期:2017-01-31
down
wechat
bug