We show that an interacting electronic system with a single ordinary or extended Van Hove point, which crosses the Fermi energy, is unstable against triplet superconductivity. The pairing mechanism is unconventional. There is no Cooper instability. Instead, pairing is due to the divergence of the density of states at a Van Hove point, leading to a superconducting quantum critical point at a finite detuning from the Van Hove point. The transition temperature is universally determined by the exponent governing the divergence of the density of states. Enhancing this exponent drastically increases T_c. The Cooper pair wave function has a non-monotonic momentum dependence with a steep slope near the gap nodes. In the absence of spin–orbit coupling, pairing fluctuations suppress a 2e spin-triplet state, but allow pairs of triplets to condense into a charge-4e singlet state at a temperature of similar order as our result.

我们表明，具有穿过费米能的单个普通或扩展范霍夫点的相互作用电子系统在三重态超导性面前是不稳定的。配对机制非常规。没有 Cooper 不稳定。相反，配对是由于范霍夫点处的状态密度发散，导致超导量子临界点与范霍夫点发生有限失谐。转变温度通常由控制状态密度发散度的指数决定。增强此指数会大大增加 T_c。Cooper 对波函数具有非单调动量依赖性，在间隙节点附近具有陡峭的斜率。在没有自旋-轨道耦合的情况下，配对波动抑制了 2e 自旋-三重态，但允许成对的三元组在与我们的结果相似数量级的温度下凝结成电荷-4e 单重态。